Grade 10 → Mechanics → Work, Energy and Power ↓
Work–energy theorem
The work-energy theorem is a principle that connects the concepts of work and energy. In simple terms, it tells us that the work done by all the forces acting on an object is equal to the change in its kinetic energy. This theorem is a fundamental concept in physics and it helps us understand how energy is transferred and transformed.
Understanding work and energy
Before getting into the work-energy theorem, let us briefly understand what we mean by work and energy in physics.
Work
In physics, work is done when a force moves an object a distance. However, not all forces do work. Only the component of the force that acts in the direction of displacement does work.
The formula for work W
is given as:
W = F × d × cos(θ)
Where:
F
is the applied force.d
is the displacement of the object.θ
is the angle between the direction of force and displacement.
Example: Imagine you are pushing a heavy box across the floor. If you apply a force of 10 Newtons and the box moves 5 meters in the same direction, the work done is:
W = 10 N × 5 m × cos(0°) = 50 Joules
Since the force is in the direction of displacement, the angle is 0 degrees, and cos(0°)
is 1.
Energy
Energy is the capacity to do work. It comes in various forms, such as kinetic energy, potential energy, thermal energy, etc.
Kinetic energy
Kinetic energy is the energy an object has due to its motion. It is given by the formula:
KE = 0.5 × m × v²
Where:
m
is the mass of the object.v
is the velocity of the object.
Example: A car with a mass of 1000 kg moving at a speed of 20 m/s has the kinetic energy:
KE = 0.5 × 1000 kg × (20 m/s)² = 200,000 Joules
Work–energy theorem
According to the work-energy theorem, the total work done by all forces acting on an object is equal to the change in its kinetic energy. Mathematically it is expressed as:
W_total = ΔKE = KE_final - KE_initial
Where:
W_total
is the total work done.ΔKE
is the change in kinetic energy.KE_initial
is the initial kinetic energy.KE_final
is the final kinetic energy.
Application of the work-energy theorem
Let us see how we can apply the work-energy theorem to different scenarios:
Example 1: Stopping the car
Imagine that a car stops due to the force of friction. The work done by friction is equal to the change in the kinetic energy of the car.
Landscape:
A car of mass 1000 kg is moving at a speed of 30 m/s. The driver applies the brake and the car stops. Calculate the work done by the brake.
Solution:
KE_initial = 0.5 × 1000 kg × (30 m/s)² = 450,000 Joules
KE_final = 0 (since the car stops)
W_total = KE_final - KE_initial = 0 - 450,000 Joules = -450,000 Joules
The negative sign indicates that the work done by the brake is opposite to the motion of the car.
Example 2: Roller coaster
Consider a roller coaster at the top of a hill. As it descends, its potential energy is converted into kinetic energy.
Landscape:
A roller coaster with a mass of 500 kg is at rest at the top of a hill 10 m high. Calculate the speed of the coaster at the bottom of the hill.
Solution:
Potential energy at the top of the hill:
PE_initial = m × g × h = 500 kg × 9.8 m/s² × 10 m = 49,000 Joules
Since the coaster is stationary at the top, KE_initial
is 0. At the bottom, all the potential energy is converted to kinetic energy:
KE_final = PE_initial = 49,000 Joules
Now use the kinetic energy formula to find the speed:
49,000 Joules = 0.5 × 500 kg × v²
v² = 49,000 / 250
v = √(196) ≈ 14 m/s
Example 3: Lifting a body
The work done while lifting a body is stored as potential energy. If it is dropped, the potential energy is converted back into kinetic energy when it falls.
Landscape:
A mass of 50 kg is raised to a height of 5 m. Calculate its speed just before the mass is dropped to the ground.
Solution:
Potential energy at 5 m:
PE_initial = m × g × h = 50 kg × 9.8 m/s² × 5 m = 2,450 Joules
Below, just before hitting the ground, all of this is converted into kinetic energy:
KE_final = PE_initial = 2,450 Joules
Using the kinetic energy formula:
2,450 Joules = 0.5 × 50 kg × v²
v² = 2,450 / 25
v = √(98) ≈ 9.9 m/s
Conclusion
The work-energy theorem provides a powerful way to analyze forces and motion in a variety of physical situations. Whether it's braking a vehicle, the thrilling descent of a roller coaster, or lifting and dropping an object, understanding how work and energy interact helps us describe and predict motion efficiently.
By understanding these fundamental principles, we not only solve theoretical problems, but also gain valuable insight into real-world mechanics. The work-energy theorem encapsulates this understanding by linking forces to changes in energy, making it an essential concept in the study of physics.