Grade 11

Grade 11Mechanicsdynamics


Free fall and terminal velocity


Introduction to free fall

The concept of free fall is pretty straightforward: it's a type of motion where an object is only affected by gravity, meaning no other forces like air resistance affect its motion. When we think of free fall in its purest form, we imagine it taking place in a vacuum where gravity is the only force.

Understanding gravity

Gravity is a force that pulls objects toward the center of the Earth. This is why when you throw an object up it comes back down. The force of gravity on an object located at or near the Earth's surface is approximately constant and its magnitude is represented by the symbol g. Its value is approximately 9.8 m/s^2.

Free fall speed

In free fall, because gravity is the only active force, all objects will experience the same acceleration due to gravity, regardless of their mass. This may seem paradoxical because we often see heavier objects falling faster in the presence of air resistance. But in a vacuum, where no air is present to slow anything down, a feather and a hammer will fall at the same rate.

Mathematical representation

Using the laws of dynamics, we can represent the free fall motion by the following equation:

V = GT

Where:

  • v is the final velocity of the object.
  • g is the acceleration due to gravity, which on Earth is about 9.8 m/s^2.
  • t is the time during which the object continued to fall.

An example of this would be calculating the velocity of an object after it has been in free fall for 5 seconds:

v = (9.8 m/s^2) times (5 s) = 49 m/s

This means that after 5 seconds, the object is moving downwards at a speed of 49 meters per second.

Distance covered in free fall

The distance fallen by an object during free fall can be calculated using this formula:

d = frac{1}{2} gt^2

Where:

  • d is the distance dropped.
  • g is the acceleration due to gravity.
  • t is autumn time.

Let's find how far an object falls in 5 seconds:

d = frac{1}{2} times 9.8 times 5^2 = 122.5  m

This calculation shows that the object will fall a distance of 122.5 meters in 5 seconds.

Free fall fantasy

Start After 1s After 2s Direction of motion

The figure above shows the trajectory of an object in free fall. Gravity pulls it straight towards the center of the Earth.

Introduction to terminal velocity

Terminal velocity is the constant speed that a freely falling object eventually reaches, when the resistance of the medium through which it is falling prevents further acceleration.

When an object falls in air (or any other fluid), it experiences a drag force opposite to the direction of its motion. This drag force depends on many factors, including the size, shape, and velocity of the object, as well as the viscosity of the medium.

The concept of terminal velocity

As an object falls, its speed increases, which also increases the drag force acting on it. Eventually, this drag force becomes equal to the force of gravity acting on the object. When these two forces balance out, the object's acceleration stops and it falls at a constant speed called terminal velocity.

Mathematical description

The resistance force F_d acting on an object can be represented as:

F_d = frac{1}{2} C rho A v^2

Where:

  • C is the drag coefficient, which depends on the shape of the object
  • rho is the density of the fluid through which the object is moving
  • A is the cross-sectional area of the object
  • v is the velocity of the object

At terminal velocity, the following equation is true:

mg = frac{1}{2} c rho a v^2_t

where v_t is the terminal velocity, and mg is the weight of the object.

Example of terminal velocity calculation

Suppose a skydiver is jumping from an airplane. The skydiver's mass is 80 kg, the cross-sectional area is 0.7 m^2, the drag coefficient for the spread-eagle position is 1.0, and the air density is 1.225 kg/m^3.

We can find the terminal velocity using the balanced force equation:

mg = frac{1}{2} c rho a v^2_t
80 times 9.8 = frac{1}{2} times 1.0 times 1.225 times 0.7 times v^2_t

Solving for v_t, we get:

784 = 0.4285v^2_t
v^2_t = frac{784}{0.4285} approx 1832.9 
v_t approx 42.82  m/s

Thus, the terminal velocity for this skydiver is about 42.82 meters per second.

Visual exploration of terminal velocity

Start Descent Increasing the speed Terminal velocity

This visualization shows the process. The object first accelerates and then moves at a constant speed to terminal velocity due to balanced forces.

Factors affecting terminal velocity

  • Shape of the object: Most aerodynamic objects have a low coefficient of drag, resulting in a high terminal velocity.
  • Cross-sectional area: Larger area increases resistance, which reduces terminal velocity.
  • Altitude: At higher altitudes the resistance decreases due to lower air density, thus increasing the terminal velocity.
  • Mass: Heavier objects have a greater gravitational force, which increases the terminal velocity.

Conclusion

Understanding the concepts of free fall and terminal velocity provides information about the motion of objects under the influence of resisting forces such as gravity and air resistance. Free fall allows us to see how gravity naturally affects motion, while terminal velocity demonstrates the balance of forces in a fluid medium.

These principles are applied in a number of real-world situations, from the design of parachutes to predicting the fall rate of various objects, ensuring safety and efficiency in a variety of fields.


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