Grade 11

Grade 11MechanicsDynamics


Conservation of momentum in one and two dimensions


Momentum is an important concept in physics. It refers to the amount of motion of an object and depends on two variables: the mass of the object and its velocity. The mathematical representation of momentum is given by the formula:

p = m * v

Here, p is speed, m is mass, and v is the velocity of the object. The unit of speed is kilogram meter per second (kg m/s).

Momentum conservation principle

The law of conservation of momentum states that in an isolated system, the total momentum before any event is equal to the total momentum after the event, provided there is no external force acting on it. Mathematically, for two colliding objects, the principle can be expressed as:

m1 * v1_initial + m2 * v2_initial = m1 * v1_final + m2 * v2_final

Understanding motion in one dimension

In one-dimensional motion, objects move in a straight line. Imagine two cars colliding on a straight road. Their interaction can be represented as follows:

Car 1: m1, v1_initial Car 2: m2, v2_initial

According to conservation of momentum:

m1 * v1_initial + m2 * v2_initial = m1 * v1_final + m2 * v2_final

This equation helps us to calculate the unknown velocities after collision.

Example problem in one dimension

Consider two ice skaters, one has a mass of 50 kg and moves at a velocity of 4 m/s, while the other has a mass of 30 kg and moves at a velocity of -2 m/s. After colliding, they join together and move as one mass. Find their velocity after the collision.

Given:

  • m1 = 50 kg, v1_initial = 4 m/s
  • m2 = 30 kg, v2_initial = -2 m/s

Using conservation of momentum:

(50 kg * 4 m/s) + (30 kg * -2 m/s) = (50 kg + 30 kg) * v_final

Simplification:

200 kg · m/s - 60 kg · m/s = 80 kg * v_final

140 kg · m/s = 80 kg * v_final

Solve for v_final:

v_final = 140 kg · m/s / 80 kg = 1.75 m/s

After the collision the velocity of both skaters is 1.75 m/s.

Motion in two dimensions

In two-dimensional motion, objects can move along different paths while making angles. Calculating motion in two dimensions involves dividing it into two perpendicular components, often the x and y axes.

Understand with an example

Picture two pucks on an air hockey table colliding at an angle. This is shown below:

Puck A: mA Puck B: mB

To calculate the final velocities, we break down the velocities of the puck into components. Using conservation of momentum for the x and y components:

mA * vA_initial_x + mB * vB_initial_x = mA * vA_final_x + mB * vB_final_x
mA * vA_initial_y + mB * vB_initial_y = mA * vA_final_y + mB * vB_final_y

Example problem in two dimensions

Suppose puck A, with a mass of 0.5 kg, moves along the x-axis at a speed of 4 m/s, and puck B, with a mass of 0.5 kg, moves along the y-axis at a speed of 3 m/s. After the collision, puck A moves at a velocity of 3 m/s, at a 37 degree angle to the x-axis. Calculate the final velocity (both magnitude and direction) of puck B.

Given:

  • mA = 0.5 kg, vA_initial = 4 m/s
  • mB = 0.5 kg, vB_initial = 3 m/s

Breaking this down into components for Puck A after the collision:

  • vA_final_x = 3 m/s * cos(37°)
  • vA_final_y = 3 m/s * sin(37°)

Calculation of components:

vA_final_x ≈ 3 m/s * 0.8 = 2.4 m/s
vA_final_y ≈ 3 m/s * 0.6 = 1.8 m/s

For conservation of momentum:

mA * vA_initial_x + mB * 0 = mA * vA_final_x + mB * vB_final_x
0.5 kg * 4 m/s = 0.5 kg * 2.4 m/s + 0.5 kg * vB_final_x

Solve for vB_final_x:

2 kg · m/s = 1.2 kg · m/s + 0.5 kg * vB_final_x
vB_final_x ≈ 1.6 m/s

And for the y-components:

0 + 0.5 kg * 3 m/s = 0.5 kg * 1.8 m/s + 0.5 kg * vB_final_y
vB_final_y ≈ 2.4 m/s

The final velocity magnitude of puck B is calculated as:

vB_final = √((vB_final_x)² + (vB_final_y)²)
vB_final ≈ √((1.6 m/s)² + (2.4 m/s)²) ≈ 2.88 m/s

To find the direction, use the following:

θ = arctan(vB_final_y / vB_final_x)
θ ≈ arctan(2.4 / 1.6) ≈ 56.3°

Therefore, after the collision, puck B moves at a speed of about 2.88 m/s at an angle of 56.3 degrees relative to the x-axis.

Conclusion

Understanding conservation of momentum helps us predict how objects behave when they collide with each other. In real life, these principles are applied in various fields such as car crash analysis, sports dynamics, and many other areas. The key to solving such problems is to carefully break down the components and apply the law of conservation in each direction independently.


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